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3 and 4 .Determinants and Matrices
easy
In the matrix $A=\left[\begin{array}{cccc}2 & 5 & 19 & -7 \\ 35 & -2 & \frac{5}{2} & 12 \\ \sqrt{3} & 1 & -5 & 17\end{array}\right]$, write :
$(i)$ The order of the matrix
$(ii)$ The number of elements,
$(iii)$ Write the elements $a_{13}, \,a_{21}, \,a_{33}, \,a_{24},\, a_{23}$
Option A
Option B
Option C
Option D
Solution
$(i)$ In the given matrix, the number of rows is $3$ and the number of columns is $4 .$ Therefore, the order of the matrix is $3 \times 4$
$(ii)$ Since the order of the matrix is $3 \times 4,$ there are $3 \times 4=12$ elements in it.
$(iii)$ $a_{13}=19,\, a_{21}=35, \,a_{33}=-5,\, a_{24}=12, \,a_{23}=\frac{5}{2}$
Standard 12
Mathematics
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