3 and 4 .Determinants and Matrices
easy

In the matrix   $A=\left[\begin{array}{cccc}2 & 5 & 19 & -7 \\ 35 & -2 & \frac{5}{2} & 12 \\ \sqrt{3} & 1 & -5 & 17\end{array}\right]$, write :

$(i)$ The order of the matrix

$(ii)$ The number of elements,

$(iii)$ Write the elements $a_{13}, \,a_{21}, \,a_{33}, \,a_{24},\, a_{23}$

Option A
Option B
Option C
Option D

Solution

$(i)$ In the given matrix, the number of rows is $3$ and the number of columns is $4 .$ Therefore, the order of the matrix is $3 \times 4$

$(ii)$ Since the order of the matrix is $3 \times 4,$ there are $3 \times 4=12$ elements in it.

$(iii)$ $a_{13}=19,\, a_{21}=35, \,a_{33}=-5,\, a_{24}=12, \,a_{23}=\frac{5}{2}$

Standard 12
Mathematics

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